4cos^2x+4sin^2x=4

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Solution for 4cos^2x+4sin^2x=4 equation: 


Simplifying
4cos2x + 4sin2x = 4

Solving
4cos2x + 4in2sx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4in2sx' to each side of the equation.
4cos2x + 4in2sx + -4in2sx = 4 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
4cos2x + 0 = 4 + -4in2sx
4cos2x = 4 + -4in2sx

Divide each side by '4os2x'.
c = o-1s-2x-1 + -1in2o-1s-1

Simplifying
c = o-1s-2x-1 + -1in2o-1s-1

Reorder the terms:
c = -1in2o-1s-1 + o-1s-2x-1

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